Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Join our platform to connect with experts ready to provide precise answers to your questions in various areas. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

Find two values of such that x² + kx + 3K - 5 = 0 will have two roots that are equal.

Sagot :

[tex]ax^2+bx+c=0\ have\ two\ roots\ if\ b^2-4ac > 0.\\-------------------------\\x^2+kx+3k-5=0\\\\a=1;\ b=k;\ c=3k-5\\\\b^2-4ac=k^2-4\cdot1\cdot(3k-5)=k^2-12k+20 > 0\\\\k^2-2k-10k+20 > 0\\\\k(k-2)-10(k-2) > 0\\\\(k-2)(k-10) > 0\\\\k=2;\ k=10\ (look\ at\ the\ picture)\\\\k\in(-\infty;\ 2)\ \cup\ (10;\ \infty)[/tex]
View image Аноним