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How do you find the derivative of y=3x+1−−−−−−√y =sqrt(3x+1)?

Sagot :

konrad509
[tex]y=\sqrt{3x+1}\\ y'=\frac{1}{2\sqrt{3x+1}}\cdot3\\ y'=\frac{3}{2\sqrt{3x+1}}[/tex]
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