Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Discover a wealth of knowledge from experts across different disciplines on our comprehensive Q&A platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

How do you find the derivative of y=xtan(x)y=x^tan(x)?

Sagot :

[tex]y=x^{\tan x}=e^{\ln x^{\tan x}}=e^{\tan x \ln x}\\ y'=e^{\tan x \ln x}\cdot(\sec^2 x\ln x+\tan x \cdot \frac{1}{x})\\ y'=x^{\tan x}(\sec^2 x\ln x+\frac{\tan x}{x})\\[/tex]
Answer is in attachment below. Please open it up in a new window to see it in full.
View image Аноним
Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.