Answered

Discover the best answers at Westonci.ca, where experts share their insights and knowledge with you. Join our Q&A platform to get precise answers from experts in diverse fields and enhance your understanding. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

how do you solve systems by substitution for
3x + 3y =-4
5x=20

Sagot :

[tex]\left\{\begin{array}{ccc}3x+3y=-4\\5x=20&\ |divide\ both\ sides\ by\ 5\end{array}\right\\\\\left\{\begin{array}{ccc}3x+3y=-4\\x=4\end{array}\right\\\\substitute:\\\\3\cdot4+3y=-4\\12+3y=-4\\3y=-4-12\\3y=-16\ \ \ \ \ \ |divide\ both\ sides\ by\ 3\\y=-\frac{16}{3}\\\\Solution:x=4\ and\ y=-\frac{16}{3}\to(4;-\frac{16}{3})[/tex]
Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.