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Answered

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Solve : (2x-3)^2-4(2x-3)+3=0

Sagot :

konrad509
[tex](2x-3)^2-4(2x-3)+3=0\\ 4x^2-12x+9-8x+12+3=0\\ 4x^2-20x+24=0\\ x^2-5x+6=0\\ x^2-2x-3x+6=0\\ x(x-2)-3(x-2)=0\\ (x-3)(x-2)=0\\ x=3 \vee x=2[/tex]
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