Coreas376
Answered

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Solve inequality √(2−x) < x.

Sagot :

konrad509
[tex][tex]\sqrt{2-x}0\\ x^2+2x-x-2>0\\ x(x+2)-1(x+2)>0\\ (x-1)(x+2)>0\\ x\in(-\infty,-2)\cup(1,\infty)\\\\ \boxed{x\in(-\infty,-2)\cup(1,2\rangle}[/tex][/tex]
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