solve for x m<AOB =4x-2,m<BOC=5x+10,m<COD=2x+14

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28-08-2014
Mathematics

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solve for x m<AOB =4x-2,m<BOC=5x+10,m<COD=2x+14

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lovemagnet lovemagnet · Answer 1 · 2014-09-24T20:20:31-04:00

lovemagnet lovemagnet

24-09-2014

what you have to do is solve for x of course stated above

4x - 2 + 5x + 10 = 2x +14
9x +8 = 2x + 14
(minus 2x from both sides)
7x + 8 = 14
(minus 8 from both sides)
7x = 7
(divide 7 from both sides)
x=1

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23brileyherbig 23brileyherbig · Answer 2 · 2019-08-19T19:12:09-04:00

23brileyherbig 23brileyherbig

19-08-2019

Answer:

Its not one because 14-8 is not 7 its 6.

Step-by-step explanation:

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solve for x m<AOB =4x-2,m<BOC=5x+10,m<COD=2x+14

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