Answered

Discover the answers to your questions at Westonci.ca, where experts share their knowledge and insights with you. Get detailed and precise answers to your questions from a dedicated community of experts on our Q&A platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

solve for x m<AOB =4x-2,m<BOC=5x+10,m<COD=2x+14


Sagot :

what you have to do is solve for x of course stated above

4x - 2 + 5x + 10 = 2x +14 
9x +8 = 2x + 14
(minus 2x from both sides)
7x + 8 = 14
(minus 8 from both sides)
7x = 7
(divide 7 from both sides)
x=1

Answer:

Its not one because 14-8 is not 7 its 6.

Step-by-step explanation: