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what is the answer to 10+7x<17

Sagot :

konrad509
[tex] 10+7x<17\\ 7x<7\\ x<1[/tex]
[tex]10+7x < 17\ \ \ \ |subtract\ 10\ from\ both\ sides\\\\7x < 7\ \ \ \ \ |divide\ both\ sides\ by\ 7\\\\x < 1\\\\x\in(-\infty;\ 1)[/tex]
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