dzr96
Answered

Welcome to Westonci.ca, where your questions are met with accurate answers from a community of experts and enthusiasts. Our Q&A platform offers a seamless experience for finding reliable answers from experts in various disciplines. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

 Use factoring to solve the following quadratic:   6x2 + 23x - 18 = 0

Sagot :

6x²+23x-18=0

(3x-2)(2x+9)=0

Therefore, x=2/3, and x=(-9)/2
TaylorBayley
6x^2+23x-18=0 -- 6*-18=-108 factors that made 23 are 27 and -4

So,
6x^2+27x-4x-18=0 -- factorise each half of the equation i.e. 6x^2+27x and 4x-18
3x(2x+9)-2(2x+9) -- the brackets are the same, that's one side, and combine the 2 other terms outside the brackets for the second bracket.

(3x-2)(2x+9)=0
3x-2=0
3x=2
x=2/3

2x+9=0
2x=-9
x=-9/2

x=2/3 or x=-9/2 -- there we go, fixed.

Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.