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Sagot :
p = m*v
conservation of momentum suggests
initial momentum equals final momentum
mv-initial = mv-final
(0.0010 kg)(50 m/s) = (0.0010 kg + 0.35 kg)v
thus:
v = (0.0010)(50)/(0.351) = 0.142 m/s
conservation of momentum suggests
initial momentum equals final momentum
mv-initial = mv-final
(0.0010 kg)(50 m/s) = (0.0010 kg + 0.35 kg)v
thus:
v = (0.0010)(50)/(0.351) = 0.142 m/s
Answer: The pellet and wood slide at a speed of 0.142 m/s.
Explanation:
To calculate the velocity of the pellet and wood after the collision, we use the equation of law of conservation of momentum, which is:
[tex]m_1u_1+m_2u_2=m_1v_1+m_2v_2[/tex]
where,
[tex]m_1[/tex] = mass of pellet = 0.001kg
[tex]u_1[/tex] = Initial velocity of pellet = 50m/s
[tex]v_1[/tex] = Final velocity of pellet = v m/s
[tex]m_2[/tex] = mass of wood = 0.36kg
[tex]u_2[/tex] = Initial velocity of wood = 0m/s
[tex]v_2[/tex] = Final velocity of wood = v m/s
Putting values in above equation, we get:
[tex](0.001\times 50)+(0.35\times 0)=(0.001+0.35)v\\\\v=0.142m/s[/tex]
Hence, the pellet and wood slide at a speed of 0.142 m/s.
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