LissaPacific818
Answered

At Westonci.ca, we connect you with experts who provide detailed answers to your most pressing questions. Start exploring now! Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

A force F of strength 20 N acts on an object of mass 3 kg as it moves a distance of 4 m. If F is perpendicular to the 4 m displacement, the work it does is equal to how many joules?

Sagot :

mashenka
Data:
[tex] F = 20 [N] [/tex]
[tex] m = 3 [kg] [/tex]
[tex] s = 4 [m] [/tex]
Work is calculated from the following formula:
[tex] W = F \cdot s \cdot cos(a) [/tex]
Where a is the angle between force vector and displacement vector. When force is perpendicular to displacement, a = 90 deg and cosine of this angle = 0.
Therefore, the work this force does = 0 [J]
AL2006
Work = (displacement) x (force in the direction of the displacement)

Since none of the force is in the direction of the displacement, the work it does
is zero. Something else is making the object move.  It's not the 20N force.
We appreciate your time. Please come back anytime for the latest information and answers to your questions. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.