Answered

Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Connect with a community of experts ready to help you find accurate solutions to your questions quickly and efficiently. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

A box is lowered using a rope. If the acceleration of the box, is 2.5 m/s2 (downward) and the tension in the rope is 31 N, what is the mass of the box (in kg)?

Sagot :

F= ma
31-mg = m(-2.5m/s2)
31= mg-2.5 m
31 = m*(9.8m/s2 -2.5 m/s2)
31 = 7.3 m
m = 31/7.3
m = 4.25 kg
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.