Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
We will use simple formula for velocity with constant acceleration.
[tex]v=v0+at[/tex] and formula for path [tex]x=x0+v0t+ \frac{1}{2}a t^{2} [/tex]
where:
v0 - initial velocity
a - constant acceleration
t- time
x - path
x0 - initial position
v0, and x0 are equal to 0 in this case, so we can simplify our formula to
[tex]v=at[/tex] and [tex]x= \frac{1}{2}a t^{2} [/tex]
We can modify first formula to get time
[tex]t= \frac{v}{a} [/tex] and substitute it to second formula.
[tex]x= \frac{1}{2}*a \frac{ v^{2}}{ a^{2} } = \frac{1}{2} \frac{ v^{2} }{a} [/tex]
Now we can find acceleration
[tex]a= \frac{1}{2} \frac{ v^{2} }{x} =2.27[/tex] m/s
[tex]v=v0+at[/tex] and formula for path [tex]x=x0+v0t+ \frac{1}{2}a t^{2} [/tex]
where:
v0 - initial velocity
a - constant acceleration
t- time
x - path
x0 - initial position
v0, and x0 are equal to 0 in this case, so we can simplify our formula to
[tex]v=at[/tex] and [tex]x= \frac{1}{2}a t^{2} [/tex]
We can modify first formula to get time
[tex]t= \frac{v}{a} [/tex] and substitute it to second formula.
[tex]x= \frac{1}{2}*a \frac{ v^{2}}{ a^{2} } = \frac{1}{2} \frac{ v^{2} }{a} [/tex]
Now we can find acceleration
[tex]a= \frac{1}{2} \frac{ v^{2} }{x} =2.27[/tex] m/s
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.
