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Sagot :
n=25/99
99n=25
----------------
100n-n=99n
Therefore:
100n-n=25
100n=25+n
100n=25.00+0.25...
100n=25.25...
n=0.252525252525......
99n=25
----------------
100n-n=99n
Therefore:
100n-n=25
100n=25+n
100n=25.00+0.25...
100n=25.25...
n=0.252525252525......
Answer:
1) Find the denominator of 25/99 in its lowest form.
The greatest common factor (GCF) of 25 and 99 is 1. Convert 25/99 to its simplest form by dividing the numerator and denominator by its GCF:
25 ÷ 1
99 ÷ 1
=
25
99
Thus, the denominator of 25/99 in its lowest form is 99.
2) Find the prime factors of the answer in Step 1.
The prime factors of 99 are all the prime numbers that you multiply together to get 99. The prime factors of 99 are:
3 x 3 x 11
3) Determine if 25/99 is terminating
A fraction is a terminating decimal if the prime factors of the denominator of the fraction in its lowest form only contain 2s and/or 5s or no prime factors at all. This is not the case here, which means that our answer is as follows:
25/99
= non-terminating
Step-by-step explanation:
A terminating decimal is a decimal number that has a finite number of decimals and does not go on indefinitely. We want to know if the decimal number you get when you divide the fraction 25/99 (25 ÷ 99) is terminating or non-terminating.
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