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Sagot :
The 'net' force acting on the box is (9 - 3) = 6 newtons
in the direction that Carlos is pushing.
Force = (mass) x (acceleration)
6 = (3) x (acceleration)
Divide each side by 3 :
2 m/s² = acceleration
in the direction that Carlos is pushing.
Force = (mass) x (acceleration)
6 = (3) x (acceleration)
Divide each side by 3 :
2 m/s² = acceleration
friction = 3 N
pushing force= 9 N
as both are opposite in direction so their net force will be = 9-3= 6N
as we know that
F = ma
re arranging the equation
a = F/m
by putting values
a = 6/3 N/kg
a= 2 m/sec²
pushing force= 9 N
as both are opposite in direction so their net force will be = 9-3= 6N
as we know that
F = ma
re arranging the equation
a = F/m
by putting values
a = 6/3 N/kg
a= 2 m/sec²
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