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Sagot :
First, establish what you already know to be true:
[tex]P = 3 + R \\ E = 2R \\ R + E = 81[/tex]
You can use these equations to solve each other. Let's take the last one, [tex]R + E = 81[/tex]. Using the additive property of equality, we find that [tex]R = 81 - E[/tex]. We now know that Mr. Richard's age is 81 minus Mr. Edward's age. If we substitute this equation into the second one, we have [tex]E = 2(81 - E)[/tex]. Now use the distributive property to simplify:
[tex]E = 162 - 2E[/tex], and solve for [tex]E[/tex]:
[tex]E = 162 - 2E \\ 3E = 162 \\ E = 54[/tex].
Now we have a definite age. Use this to find the other two ages:
[tex]R + 54 = 81 \\ R = 27[/tex]
and
[tex]27 = 3 + P \\ -P + 27 = 3 \\ -P = -24 \\ P = 24[/tex].
We now know that Ms. Pacheo is 24, Mr. Edwards is 54, and Mr. Richard's is 27! :D
[tex]P = 3 + R \\ E = 2R \\ R + E = 81[/tex]
You can use these equations to solve each other. Let's take the last one, [tex]R + E = 81[/tex]. Using the additive property of equality, we find that [tex]R = 81 - E[/tex]. We now know that Mr. Richard's age is 81 minus Mr. Edward's age. If we substitute this equation into the second one, we have [tex]E = 2(81 - E)[/tex]. Now use the distributive property to simplify:
[tex]E = 162 - 2E[/tex], and solve for [tex]E[/tex]:
[tex]E = 162 - 2E \\ 3E = 162 \\ E = 54[/tex].
Now we have a definite age. Use this to find the other two ages:
[tex]R + 54 = 81 \\ R = 27[/tex]
and
[tex]27 = 3 + P \\ -P + 27 = 3 \\ -P = -24 \\ P = 24[/tex].
We now know that Ms. Pacheo is 24, Mr. Edwards is 54, and Mr. Richard's is 27! :D
Mr edwards = Mr r x 2
Mr r = Mr p - 3 = Mr e ÷ 2. Mr p = 30
Mr e + Mr r = 81. Mr e = 54
Mr p = Mr r + 3. Mr r = 27
Mr Edwards = 2(Mr p - 3)
Mr e = 2(mr p) - 6
Mr r = [2(Mr p) -6] ÷ 2
Mr r = [2( Mr r + 3) - 6] ÷ 2
2(Mr r) + (Mr p - 3) = 81
2(Mr p -3) + (Mr p - 3) = 81
3(Mr p - 3) = 81
3(Mr p) - 9 = 81. Hope this helps!!!
3(Mr p) + 9 = 81 + 9
3(Mr p) = 90
Mr p = 90 ÷ 3
Mr p = 30
Mr r = Mr p - 3 = Mr e ÷ 2. Mr p = 30
Mr e + Mr r = 81. Mr e = 54
Mr p = Mr r + 3. Mr r = 27
Mr Edwards = 2(Mr p - 3)
Mr e = 2(mr p) - 6
Mr r = [2(Mr p) -6] ÷ 2
Mr r = [2( Mr r + 3) - 6] ÷ 2
2(Mr r) + (Mr p - 3) = 81
2(Mr p -3) + (Mr p - 3) = 81
3(Mr p - 3) = 81
3(Mr p) - 9 = 81. Hope this helps!!!
3(Mr p) + 9 = 81 + 9
3(Mr p) = 90
Mr p = 90 ÷ 3
Mr p = 30
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