Discover a world of knowledge at Westonci.ca, where experts and enthusiasts come together to answer your questions. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
[tex]C=2 \pi R \\ \\ C=16ft \\ \\ 2\pi R=16 => \boxed{R=\frac{16}{2\pi}=\frac{8}{\pi}} \\ \\ R=\frac{8}{\pi}=\frac{8}{3.14} \\ \\\boxed{\boxed{R \approx 2.5}}[/tex]
[tex]The\ circumference\ of\ a\ circle:C=2\pi r\ \ \ \ (r-radius)\\\\C=16ft\\\\2\pi r=16\ \ \ \ \ \ |divide\ both\ sides\ by\ 2\pi\\\\r=\frac{16}{2\pi}\\\\r=\frac{8}{\pi}\\\\we\ accept\ the\ approximation\ of\ \pi\approx3.14\\\\r=\frac{8}{\pi}\approx\frac{8}{3.14}\approx2.5\ (ft)[/tex]
Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.