Answered

Westonci.ca is the premier destination for reliable answers to your questions, brought to you by a community of experts. Get immediate and reliable solutions to your questions from a community of experienced experts on our Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

factor completely and check mentally 6x^3-9x^2-12x

Sagot :

luana
[tex]6x^3-9x^2-12x=x(6x^2-9x-12)=\\\\Finding\ roots\ of\ equation:\\6x^2-9x-12=0\\\\ \Delta=b^2-4ac\\\\a=6,\ b=-9,\ c=-12 \\\\\Delta=(-9)^2-4*6*(-12)=81+288=369\\\\ \sqrt{\Delta}=3\sqrt{41}\\\\x_1=\frac{-b-\sqrt{\Delta}}{2a}\ \ x_1=\frac{9-3\sqrt{41}}{2*6}=\frac{3-\sqrt{41}}{4}\\x_2=\frac{-b+\sqrt{\Delta}}{2a}\ \ x_2=\frac{9+3\sqrt{41}}{2*6}=\frac{3+\sqrt{41}}{4}\\ 6x^2-9x-12=(x-\frac{3+\sqrt{41}}{4})(x-\frac{3-\sqrt{41}}{4})[/tex][tex]so \\\\ \textbf{Answer} \\ 6x^3-9x^2-12x=x(6x^2-9x-12)=\\ \underline{x(x-\frac{3+\sqrt{41}}{4})(x-\frac{3-\sqrt{41}}{4})}[/tex]
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.