Welcome to Westonci.ca, where you can find answers to all your questions from a community of experienced professionals. Join our Q&A platform to connect with experts dedicated to providing precise answers to your questions in different areas. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
I assume that 4 2/3 is 4 and 2/3, not 4 * 2/3. If so, 4 2/3 is as much as 14/3.
A. 4/3 (x + 2) = 4/3x + 8/3
B. 1/3 (4x + 6) = 4/3x + 2
C. 2/3 (2x + 4) = 4/3x + 8/3
D. 2/3 (2x + 7) = 4/3x + 14/3
It means that D is correct.
A. 4/3 (x + 2) = 4/3x + 8/3
B. 1/3 (4x + 6) = 4/3x + 2
C. 2/3 (2x + 4) = 4/3x + 8/3
D. 2/3 (2x + 7) = 4/3x + 14/3
It means that D is correct.
For this case we have the following expression:
[tex] \frac{4}{3}x + 4\frac{2}{3} [/tex]
The first thing we must do for this case is to write the mixed number as a fraction.
We have then:
[tex] \frac{4}{3}x + \frac{14}{3} [/tex]
Then, we can do common factor 2/3 in the expression.
We have then:
[tex] \frac{2}{3}(2x + 7) [/tex]
Answer:
An equivalent expression is:
[tex] \frac{2}{3}(2x + 7) [/tex]
Option D
Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.