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Sagot :
I assume that 4 2/3 is 4 and 2/3, not 4 * 2/3. If so, 4 2/3 is as much as 14/3.
A. 4/3 (x + 2) = 4/3x + 8/3
B. 1/3 (4x + 6) = 4/3x + 2
C. 2/3 (2x + 4) = 4/3x + 8/3
D. 2/3 (2x + 7) = 4/3x + 14/3
It means that D is correct.
A. 4/3 (x + 2) = 4/3x + 8/3
B. 1/3 (4x + 6) = 4/3x + 2
C. 2/3 (2x + 4) = 4/3x + 8/3
D. 2/3 (2x + 7) = 4/3x + 14/3
It means that D is correct.
For this case we have the following expression:
[tex] \frac{4}{3}x + 4\frac{2}{3} [/tex]
The first thing we must do for this case is to write the mixed number as a fraction.
We have then:
[tex] \frac{4}{3}x + \frac{14}{3} [/tex]
Then, we can do common factor 2/3 in the expression.
We have then:
[tex] \frac{2}{3}(2x + 7) [/tex]
Answer:
An equivalent expression is:
[tex] \frac{2}{3}(2x + 7) [/tex]
Option D
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