Answered

At Westonci.ca, we connect you with experts who provide detailed answers to your most pressing questions. Start exploring now! Get detailed and precise answers to your questions from a dedicated community of experts on our Q&A platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

please help me                          llxl+2l=2

Sagot :

naǫ
[tex]||x|+2|=2[/tex]

if x≥0 then |x|=x
if x<0 then |x|=-x

1) for x≥0

[tex]|x+2|=2 \\ x+2=2 \ \lor \ x+2=-2 \\ x=0 \in D \ \lor \ x=-4 \notin D[/tex]


2) for x<0

[tex]|-x+2|=2 \\ -x+2=2 \ \lor \ -x+2=-2 \\ -x=0 \ \lor \ -x=-4 \\ x=0 \notin D \ \lor \ x=4 \notin D[/tex]

The answer is:
[tex]x=0[/tex]
There is only one solution to the problem and that is x=0.
View image Аноним
Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.