Answered

Find the best answers to your questions at Westonci.ca, where experts and enthusiasts provide accurate, reliable information. Connect with professionals on our platform to receive accurate answers to your questions quickly and efficiently. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

Jerry is experimenting with chemicals in the laboratory. He mixes a solution that is 10% acid with a solution that is 30% acid. How much of the 10% acid solution will be needed to make 40 liters of a solution that is 25% acid?

Sagot :

naǫ
The formula:
[tex]\hbox{volume percent} = \frac{\hbox{volume of solute}}{\hbox{volume of solution}} \cdot 100\%[/tex]

Data:
[tex]\hbox{volume percent}_1 =10\% \\ \hbox{volume of solution}_1= x \\ \hbox{volume of solute}_1 = 10\% x=0.1x \\ \\ \hbox{volume percent}_2 =30\% \\ \hbox{volume of solution}_2= y \\ \hbox{volume of solute}_2 = 30\% y=0.3x \\ \\ \hbox{volume percent}_3 =25\% \\ \hbox{volume of solution}_3= 40 \ l \\
\hbox{volume of solute}_1 = 25\% \cdot 40 \ l =10 \ l \\[/tex]

You need to make 40 l of a solution with 10 l of solute.
[tex]\hbox{volume of solute}_1+ \hbox{volume of solute}_2 = 10 \ l \\ \hbox{volume of solution}_1 + \hbox{volume of solution}_2= 40 \ l[/tex]

Therefore:
[tex] \left \{ {{0.1x+0.3y=10} \atop {x+y=40}} \right. \\ \\ \left \{ {{x+3y=100} \atop {-x-y=-40}} \right. \\ x-x+3y-y=100-40 \\ 2y=60 \\ y=30 \\ -x-30=-40 \\ -x=-10 \\ x=10 \\ \left \{ {{x=10} \atop {y=30}} \right. [/tex]

You will need 10 liters of the 10% acid.
Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. We hope this was helpful. Please come back whenever you need more information or answers to your queries. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.