Norals485
Answered

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Find the limit as x approaches infinity of y=arccos(1+x21+2x2)y=arccos((1+x^2)/(1+2x^2))?

Sagot :

pepe11
if x approach infinity then (x² + 1)/(2x² +1) = 1/2 then lim as x  approach infinity
lim y = arccos 1/2 = 1.047
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