Answered

Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

A 1.8-kg object moves in the x direction according to the following function:


x(t) = 2t2 + 3t − 5
(SI units). What is the force on the object after 2.7 s?

Sagot :

AL2006
Well, if the position is    x(t)  =  2t² + 3t - 5

then the speed is          x ' (t)  =  4t + 3    (first derivative of  'x'  wrt  't')

and the acceleration is     x ' ' (t)  =  4      (second derivative of  'x'  wrt  't')

Apparently, then, the acceleration is constant, and is not a function of time.

After 2.7 seconds or 2.7 years, the acceleration is  4 .

Force = (mass) x (acceleration)

Force =  (1.8)    x      (4)

Force =            7.2 newtons
We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.