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Sagot :
if AE is x+50, then the whole thing must be x=50.
if a portion of that, CE, is x+32, then the rest of it, AC, must be x+18.
Because no matter what X is, 32+18=50.
if a portion of that, CE, is x+32, then the rest of it, AC, must be x+18.
Because no matter what X is, 32+18=50.
Answer:
AC= 18
Step-by-step explanation:
It is given that:
Points A,B,C,D, and E are collinear and in that order.
AE = x+50 and CE = x+32.
Now, we know that the length of the line segment AC is equal to the length of the line segment AE minus the length of the line segment CE.
i.e.
AC=AE-CE
i.e.
AC= x+50-(x+32)
AC=x+50-x-32
( Since if the sign before the parentheses is negative then the terms comes out of the parentheses with a opposite sign )
Hence, on combining the like terms we have:
AC=x-x+50-32
AC=0+18
Hence, we get:
AC= 18
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