AnalisaCollaco359
Answered

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A balloon holds 20.0 liters of helium at 10.0°C. If the temperature increases to 50.0°C, and the pressure does
not change, what will be the new volume of the balloon?

Sagot :

Volum at the beginning: [tex]V_{1}=10[/tex]
Volum at the end: 
[tex]V_{2}=V_{1}*(1+ \alpha* (t_{2}-t_{1}))[/tex]
[tex]t_{2}-t_{1}=50-10=40[/tex]
α for helium = [tex]0,003658\frac{1}{C}[/tex]
As the result you get:
[tex]V_{2}=20*(1+0,003658*40)=22,9264 l[/tex]
Final volume of the balloon is 22,9264 liters.

(Only if it doesn't explode during being heated ;) just a joke)

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