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Solving systems of equations by substitution
Y=6x y=5x+7

Sagot :

TaylorBayley
y=6x (1)
y=5x-7 (2)

Substitute y into (2)
(6x)=5x-7 -- subtract 5x from both sides
x=-7

Sub x into 1
y=6(-7)
y=-42

x=-7
y=-42
First substitute 'y' in 2nd equation by right side of 1st one and you get:
[tex]Y=6x[/tex]
[tex]6x=5x+7[/tex]
now substract 5x from both sides of 2nd equal and you get:
[tex]6x-5x=5x+7-5x[/tex]
as a result of the equal above you get:
[tex]x=7[/tex]
now substitute x in very first equation by the result from above (x=7):
[tex]Y=6*7=42[/tex]
[tex]x=7[/tex]
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