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In an 8.00 km race, one runner runs at a steady 11.0 km/h and other runs at 14.8 km/h. How far from the finish line is the slower runner when the fast runner fisnishes the race?

Sagot :

the fast runner will cover 8 km by time = t = d/v =8/14.8 = 0.54 hour
at that time ( 0.54 hr ) the slower runner would  cover d = v*t = 11*.0.54 = 5.94 km
So the slower would be at a distance = 8km - 5.94km =2.06 km from the finish line.
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