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Sagot :
[tex]|DE|=5\\|\angle EDF|=55^o\\|FE|=?\\\\tan|\angle EDF|=\frac{|FE|}{|DE|}\\\\tan55^o\approx1.4281\\\\therefore:\\\frac{|FE|}{5}\approx1.4281\Rightarrow|FE|\approx1.4281\times5=7.1405\approx7.1[/tex]
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