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How do you balance the equation NO2 + H2 →-> NH3 +H2O using the oxidation number method?

Sagot :

[tex]NO_2 + H_2 \to NH_3 + H_2 O[/tex]

[tex]2NO_2 + 7H_2 \to 2NH_3 + 4H_2 O [/tex]

The balanced equation for the given chemical reaction on the basis of oxidation number method is 2NO₂ + 7H₂ → 2NH₃ + 4H₂O.

What is oxidation number?

Oxidation number of any element gives idea about the number of exchangeable electrons from the outer most shell of the element.

Given chemical reaction is:
NO₂ + H₂ → NH₃ + H₂O

Above chemical reaction is not balanced as number of entities present on the left side is not equal to the number of entities present on the right side of the reaction.

  • Oxidation state of nitrogen changes from +4 to -3 from left side to right side.
  • Oxidation state of hydrogen changes from 0 to +1 from left side to right side.

So, balanced chemical reaction is:

2NO₂ + 7H₂ → 2NH₃ + 4H₂O

In the above reaction now all elements are present in equal quantity on the both sides.

Hence balanced equation is written above.

To know more about oxidation number, visit the below link:
https://brainly.com/question/25962988

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