Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Discover solutions to your questions from experienced professionals across multiple fields on our comprehensive Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
Verrry interesting !
In the fraction at the end of the equation ... c/ac ... the numerator and denominator can both be divided by 'c', and the fraction becomes 1/a .
Then the equation becomes d = a + b + 1/a
The equation can't be solved for 'c', because there is no relationship between 'c' and any of the other terms. 'c' can be anything at all, and it has no effect on anything else in the equation.
Or, to put a finer point on it, 'c' is not a function of 'a', 'b', or 'd' .
In the fraction at the end of the equation ... c/ac ... the numerator and denominator can both be divided by 'c', and the fraction becomes 1/a .
Then the equation becomes d = a + b + 1/a
The equation can't be solved for 'c', because there is no relationship between 'c' and any of the other terms. 'c' can be anything at all, and it has no effect on anything else in the equation.
Or, to put a finer point on it, 'c' is not a function of 'a', 'b', or 'd' .
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.