Answered

Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Join our Q&A platform and get accurate answers to all your questions from professionals across multiple disciplines. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

(ax + b) × (cx + d) =

Sagot :

crisforp
a * c *[tex] x^{2} [/tex]  +  a * x *d  +  b * c* x  +  b * d  = ac[tex] x^{2} [/tex] + ( ad + bc)x + bd.
AL2006
These are easy if you know  " FOIL ".  That's a procedure that takes you through multiplying two binomials.

FOIL stands for
-- First terms
-- Outside terms
-- Inside terms
-- Last terms

and that's how you keep everything straight while you're doing it.

(ax + b) x (cx + d)

Multiply First terms . . . 'ax' times 'cx' =  acx²

Multiply Outside terms . . . 'ax' times 'd'  =  adx

Multiply Inside terms . . .  'b' times 'cx'  =  bcx

Multiply Last terms . . .  'b' times 'd' =  bd

Now addummup:

(ax + b) x (cx + d)  =  acx² + adx + bcx + bd

From there, you can look for opportunities to make it look cleaner and prettier ... factoring, combining like terms, etc.

Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.