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Sagot :
You're going to use the constant acceleration motion equation for velocity and displacement:
(V)final²=(V)initial²+2a(Δx)
Given:
a=0.500m/s²
Δx=4.75m
(V)intial=0m
(V)final= UNKNOWN
(V)final= 2.179m/s
(V)final²=(V)initial²+2a(Δx)
Given:
a=0.500m/s²
Δx=4.75m
(V)intial=0m
(V)final= UNKNOWN
(V)final= 2.179m/s
Hello!
A person pushing a stroller start from rest uniformly accelerating at a rate of 0.500 m/s². What is the velocity of the stroller after it traveled 4.75 m ?
We have the following data:
a (acceleration) = 0.500 m/s²
Vf (final velocity) = ? (in m/s)
Vi (initial velocity) = 0 m/s
Δx (displacement) = 4.75 m
Solving:
Let's apply the Torricelli Equation, to find the velocity of the stroller, let's see:
[tex]V_f^2 = V_i^2 + 2*a*\Delta{x}[/tex]
[tex]V_f^2 = 0^2 + 2*0.500*4.75[/tex]
[tex]V_f^2 = 0 + 4.75[/tex]
[tex]V_f^2 = 4.75[/tex]
[tex]V_f = \sqrt{4.75}[/tex]
[tex]\boxed{\boxed{V_f \approx 2.18\:m/s}}\:\:\:\:\:\:\bf\blue{\checkmark}\bf\green{\checkmark}\bf\red{\checkmark}[/tex]
Answer:
The velocity of the stroller is approximately 2.18 m/s
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[tex]\bf\red{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}[/tex]
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