lala01198
Answered

Discover the best answers at Westonci.ca, where experts share their insights and knowledge with you. Join our platform to connect with experts ready to provide accurate answers to your questions in various fields. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

Find the area of the following:
-square whose sides are (x+1) in length

Sagot :

mattgent8
Area of Square = Base*Height 
Base=(x+1) Height=(x+1)
Therefore Area=(x+1)(x+1) or (x+1)^2
By expanding the brackets e.g. x*x is x^2 then x*1 is x and so on you get:
x^2+x+x+1 this simplfies to x^2+2x+1
Area = x^2=2x+1
Unless they have given you a value for x, this is the equation for the area of said square.

Answer:

Area of the square = [tex]x^2+2x+1[/tex]

Step-by-step explanation:

We need to find the area of the square

The side length of the square is (x+1)

Area of the square formula is (side)^2

Replace side with x+1

So the area of the square = [tex](x+1)^2[/tex]

[tex](x+1)^2= (x+1)(x+1)= x^2+x+x+1= x^2+2x+1[/tex]

Area of the square = [tex]x^2+2x+1[/tex]

Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.