Answered

Discover the answers you need at Westonci.ca, a dynamic Q&A platform where knowledge is shared freely by a community of experts. Join our Q&A platform and connect with professionals ready to provide precise answers to your questions in various areas. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

Find two consecutive even integers such that the sum of the smaller and 5 times the larger is 202.

Sagot :

STOPCHEATINGK12ER
so the equation hmmm is this x+5(x+2)=202 now a little math x+5x+10=202 and hmm 6x=192 and x=32 and x+2 is 34 even number has spaces of 2 so i used x+2. Uh yeah whooooo! hows that babe ;)
n; n+2 - two consecutive even integers

n + 5(n + 2) = 202

n + 5n + 10 = 202

6n + 10 = 202      |subtract 10 from both sides

6n = 192      |divide both sides by 6

n = 32

Answer: 32 and 34.
Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.