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Find two consecutive even integers such that the sum of the smaller and 5 times the larger is 202.

Sagot :

STOPCHEATINGK12ER
so the equation hmmm is this x+5(x+2)=202 now a little math x+5x+10=202 and hmm 6x=192 and x=32 and x+2 is 34 even number has spaces of 2 so i used x+2. Uh yeah whooooo! hows that babe ;)
n; n+2 - two consecutive even integers

n + 5(n + 2) = 202

n + 5n + 10 = 202

6n + 10 = 202      |subtract 10 from both sides

6n = 192      |divide both sides by 6

n = 32

Answer: 32 and 34.
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