Sisler554
Answered

Welcome to Westonci.ca, where curiosity meets expertise. Ask any question and receive fast, accurate answers from our knowledgeable community. Discover precise answers to your questions from a wide range of experts on our user-friendly Q&A platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

The launch site for trigon balloon co. is 250 ft above sea level. A hot air balloon is launched from the site and begins to rise at a rate of 110 ft/min. At the same time, another balloon 2200 ft above sea level begins to descend at a rate of 150 ft/min. A. How long will it be unit the balloons are at the same elevation? B. What will their elevation be then?

Sagot :

SecretIndex
Set up the equations as equal: 
110x+250=-150x+2200
Add 150x to both sides:
260x+250=2200
Subtract 250 from both sides.
260x=1950
Divide both sides by 260.
x=7.5
A: They will meet at 7.5 minutes after launch
Plug in 7.5:
110(7.5)+250=11*75+250=825+250=1075
B: They will meet at 1075 feet

We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.