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The sum of three consecutive odd integers is 195. Find the three integers.

Sagot :

a+a+2+a+4=195
3a+6=195
3a=189
a=63

a+2=65
a+4=67
Good afternoon, 

x= first odd integer 
x+2 = second odd integer
x+4= third intenger

The sum of the trhree integer is 195, so:

x + (x+2) + (x+4) = 195
3x = 195 - 4 - 2
3x=189
x= 63

Then the Answer is: 63, 65 and 67