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Sagot :
Well, there is a system:
[tex]L=100*2^{\frac{t}{10}}[/tex]
[tex]p=2000000+2000000*\frac{t}{10}[/tex]
[tex]L=.2P[/tex]
I'd guess you need the last equation in a different form: [tex].2=\frac{L}{P}[/tex]
[tex]L=100*2^{\frac{t}{10}}[/tex]
[tex]p=2000000+2000000*\frac{t}{10}[/tex]
[tex]L=.2P[/tex]
I'd guess you need the last equation in a different form: [tex].2=\frac{L}{P}[/tex]
The equation is [tex]\boxed{0.2 = \frac{{100 \times {2^{\dfrac{t}{{10}}}}}}{{2000000 + 2000000 \times \dfrac{t}{{10}}}}}.[/tex]
Further explanation:
Explanation:
In the year 1900 the population of the country is 2 million.
The number of lawyers in 1900 is 100.
Every 10 years the number of lawyers doubles and the population increases by 2 million.
Consider number of the lawyer as [tex]x[/tex] and the population of the country as [tex]y[/tex].
The expression of increasing the number of lawyers can be expressed as follows,
[tex]x = 100 \times {2^{\dfrac{t}{{10}}}}[/tex]
The population of the country can be expressed as follows,
[tex]y = 2000000 + 2000000 \times \dfrac{t}{{10}}[/tex]
20 percent of the populations are Lawyers.
[tex]\begin{aligned}0.2y&= x\\0.2&= \frac{x}{y}\\0.2&= \frac{{100 \times {2^{\frac{t}{{10}}}}}}{{2000000\left( {1 + \frac{t}{{10}}} \right)}}\\\end{aligned}[/tex]
The equation is [tex]\boxed{0.2 = \dfrac{{100 \times {2^{\dfrac{t}{{10}}}}}}{{2000000 + 2000000 \times \dfrac{t}{{10}}}}}.[/tex]
Learn more:
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Answer details:
Grade: High School
Subject: Mathematics
Chapter: Exponential equation
Keywords: lawyers, in the year 1900, 100 lawyers, 2 million people, 10 years, Country, Acirema, lawyers double, population increase by 2 million, t, number of years, 1903, equation, involving t, solution, 20 percent population are laywers.
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