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The vertex form of the equation of a parabola is y = 4(x - 2)2 - 1. What is the standard form of the equation?
A.y = 4x2 - 16x + 2
B.y = 4x2 - 16x + 15
C.y = 4x2 - 3
D.y = 16x2 - 5 ?

Sagot :

AndyBryer
Ok so your original equation was y=4(x-2)²-1
Therefore we need to expand the bracket to find the original equation.
To do this we need to find (x-2)²=x²-4x+4
Now we multiply this by 4 and subtract 1
4x²-16x+15 Therefore B is the answer
eah
y = 4(x - 2)² - 1
y = 4(x² - 4x + 4) - 1 
y = 4x² - 16x + 16 - 1
y = 4x² - 16x + 15

y = B(y)
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