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How far will a freely falling object fall from rest in six seconds?

Sagot :

schuhplattler42
Tabulate, then find the proper equation, then solve.

vi=0
vf=?
t=6s
a=g=9.8m/s²

vf=vi+at
vf=gt
vf= (find this yourself)
AL2006
Here are two ways to do it:

Way #1:
-- You know that gravity accelerates things that are falling freely, adding 9.8 m/s to their speed every second.

-- After 6 seconds, an object that fell from rest winds up falling at (9.8 x 6) = 58.8m/s.

-- During that time, its average speed was 1/2(0 + 58.8) = 29.4 m/s .

-- In 6 seconds, at an average speed of 29.4 m/s, it covers (29.4 x 6) = 176.4meters.

Way #2:
This way only works if you remember the formula for the distance covered during uniform acceleration.

             D  =  1/2 (acceleration) (time)²

Acceleration = gravity = 9.8 m/s²
Time  =  6 seconds

           D  =  1/2 (9.8) (6)²  =  176.4 meters.
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