At Westonci.ca, we connect you with the answers you need, thanks to our active and informed community. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
There are an infinite number of solutions, so I don't plan to list them all.
I'll list two of them, and then describe how to get all of the rest.
You said that 2cos(x) - 1 = 0
Add 1 to each side: 2cos(x) = 1
Divide each side by 2: cos(x) = 1/2
The angles whose cosine is 1/2 are 60 degrees, 300 degrees,
and any multiple of 360 degrees added to either of those.
I'll list two of them, and then describe how to get all of the rest.
You said that 2cos(x) - 1 = 0
Add 1 to each side: 2cos(x) = 1
Divide each side by 2: cos(x) = 1/2
The angles whose cosine is 1/2 are 60 degrees, 300 degrees,
and any multiple of 360 degrees added to either of those.
2cosx=1
cosx=1/2
x=cos∧-1(1/2)
x=60degrees or 360-60=300degrees
depending on your limits if in radians pi/3 and 5pi/3
cosx=1/2
x=cos∧-1(1/2)
x=60degrees or 360-60=300degrees
depending on your limits if in radians pi/3 and 5pi/3
We hope this was helpful. Please come back whenever you need more information or answers to your queries. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.