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Sagot :
7x2=14 and 7 is a prime number so is only divisible by itself and 1
Factors of 14: 1, 14, 2, 7
Multiples of 2: 2, 4, 6, 8, 10, 12, 14, 16, 18, etc.
From this, we see that 14 and 2 are factors of 14 and multiples of 2. Therefore, we see there are two numbers that are remaining.
They are: 1 and 7
Multiples of 2: 2, 4, 6, 8, 10, 12, 14, 16, 18, etc.
From this, we see that 14 and 2 are factors of 14 and multiples of 2. Therefore, we see there are two numbers that are remaining.
They are: 1 and 7
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