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Marcus, Sally and Sammy decided to share 20 sweets. Marcus took 8 sweets and sally took three times as many as Sammy. how many sweets did Sammy receive?

Sagot :

luana
[tex]x-\ amount\ of\ sweets\ which\ Sammy\ took\\\\ 3x-\ amount\ of\ sweets\ which\ Sally\ took\\\\\\ 3x+x+8=20\\\\ 4x+8=20\ \ \ |Subtract\ 8\\\\ 4x=12\ \ \ |Divide\ by\ 4\\\\ x=3\\\\Samy\ received\ 3\ sweets.[/tex]
Illuminati750
Hello, 

they decided to share 20 sweets, but Marcus took 8 sweets, so:

20-8=12

We have 12 sweets left.

x= number of sweets that Sally took
y= number of sweets that Sammy took

We know that Sally took three times as many as Sammy, so:
x=3y

There are 12 sweets:

x+y=12

Replacing x:

3y+y=12
4y=12
y=3

x=3*(3)
x=9 

Answer: Sally took 9 sweets and Sammy 3
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