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Sagot :
[tex]x-\ amount\ of\ sweets\ which\ Sammy\ took\\\\
3x-\ amount\ of\ sweets\ which\ Sally\ took\\\\\\
3x+x+8=20\\\\
4x+8=20\ \ \ |Subtract\ 8\\\\
4x=12\ \ \ |Divide\ by\ 4\\\\
x=3\\\\Samy\ received\ 3\ sweets.[/tex]
Hello,
they decided to share 20 sweets, but Marcus took 8 sweets, so:
20-8=12
We have 12 sweets left.
x= number of sweets that Sally took
y= number of sweets that Sammy took
We know that Sally took three times as many as Sammy, so:
x=3y
There are 12 sweets:
x+y=12
Replacing x:
3y+y=12
4y=12
y=3
x=3*(3)
x=9
Answer: Sally took 9 sweets and Sammy 3
they decided to share 20 sweets, but Marcus took 8 sweets, so:
20-8=12
We have 12 sweets left.
x= number of sweets that Sally took
y= number of sweets that Sammy took
We know that Sally took three times as many as Sammy, so:
x=3y
There are 12 sweets:
x+y=12
Replacing x:
3y+y=12
4y=12
y=3
x=3*(3)
x=9
Answer: Sally took 9 sweets and Sammy 3
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