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Sagot :
3Cl2 + 2Al ---> 2AlCl3
you're pretty much trying to find the lcm to balance the equation
aka you have 2 Cl's on one side and 3 on the other...
lcm=6 so put a 3 before Cl2 and a 2 before AlCl3 (since thats one big compound you cant divide it)
now since Al has 2 on one side, you need to make sure it has the same amound on the other... so 3, 2 --> 2
you're pretty much trying to find the lcm to balance the equation
aka you have 2 Cl's on one side and 3 on the other...
lcm=6 so put a 3 before Cl2 and a 2 before AlCl3 (since thats one big compound you cant divide it)
now since Al has 2 on one side, you need to make sure it has the same amound on the other... so 3, 2 --> 2
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