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how do I solve this algebra problem: 2(4a-12)+3a=6a+1

Sagot :

luana
[tex]2(4a-12)+3a=6a+1\\\\ 8a-24+3a=6a+1\\\\ 11a-24=6a+1\ \ \ |Subtract\ 6a\\\\ 5a-24=1\ \ \ |Add\ 24\\\\ 5a=25\ \ \ |Divide\ by\ 5\\\\ a=5\\\\Solution\ is\ a=5.[/tex]
mariamikayla
[tex]2(4a-12)+3a=6a+1 \\\\ 8a-24+3a=6a+1 \\\\ 11a-24=6a+1 \\\\ 11a-6a=1+24 \\\\ 5a=25 \\\\ \boxed{a=\frac{25}{5}=5}[/tex]
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