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Three different whole numbers add up to 31.
The first number is multiple of 3
The second number is multiple of 4
The third number is multiple of 5.
What could the numbers be???

Sagot :

SlowZasob
Let's find the least possibilities:

First number: 6
Second number: 8
Third number: 10

6 + 8 + 10 = 24

Now we can see that we are still missing 31 - 24 = 7.

7 can be gained by adding 3 and 4, so:

First number: 6 + 3 = 9
Second number: 8 + 4 = 12
Third number: 10

9 + 12 + 10 = 31
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