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Suppose y varies directly as x, and y =16 when x=8. Find y when x=16

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 y varies directly as x, and y =16 when x=8. Find y when x=16
y is double x
so when x=16
y=16x2 which equals 32
carlosego

For this case, since the variation is direct then we have a relation of the form:

[tex] y = kx
[/tex]

Where,

k: proportionality constant

To find k we substitute the following data:

y = 16 when x = 8

We have then:

[tex] 16 = k8
[/tex]

Clearing the value of k we have:

[tex] k = \frac{16}{8}

k = 2
[/tex]

Then, the equation is:

[tex] y = 2x
[/tex]

Substituting the value of x = 16 we have:

[tex] y = 2 (16)

y = 32
[/tex]

Answer:

The value of y for x = 16 is:

[tex] y = 32 [/tex]

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