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3/x+1 -1/2 = 1/3x+3 please help solve

Sagot :

mariamikayla
[tex]\frac{3}{x+1}^{(6}-\frac{1}{2}^{(3x+3}=\frac{1}{3x+3}^{(2} \\\\ 18-3x-3=2 \\\\ -3x+15=2\\\\ -3x=2-15 \\\\-3x=-13 \\\\ \boxed{x=\frac{13}{3}}[/tex]
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