At Westonci.ca, we connect you with the best answers from a community of experienced and knowledgeable individuals. Get quick and reliable solutions to your questions from knowledgeable professionals on our comprehensive Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

the width of a rectangle is 33 centimeters. the perimeter is at least 776 centimeters.
what inequality expresses the length of the rectangle?
what is the area of the rectangle in square centimeters?


Sagot :

luana
[tex]x-\ length\\ width=33cm\\\\ Perimeter=2width+2length\\\\ 2x+2*33>776\\ 2x+66>776\ \ |Subtract\ 66\\2x>710\\\boxed{x>355cm}\\\\Area=width*length\\ Area>355*33\\ \boxed{Area>11715cm^2} [/tex]

Answer:

Width of the rectangle is given to be 33 centimeters

Let the Length of the rectangle be x centimeters

So, Perimeter of rectangle is given by formula : Perimeter = 2 × (Length + Width)

⇒ Perimeter = 2 × (x + 33)

⇒ Perimeter = 2x + 66

Now, The perimeter of the rectangle is at least 776 centimeters

⇒ Perimeter > 2x + 66

⇒ 776 > 2x + 66

⇒ 2x < 710

⇒ x < 355

So, The length of the rectangle must be less than 355 cm

⇒ Area of the rectangle < 355 × 33

⇒ Area of the rectangle < 11715 cm²

Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.