Answered

Discover answers to your most pressing questions at Westonci.ca, the ultimate Q&A platform that connects you with expert solutions. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

the area of a rectangular wall of a barn is 40 square feet. its length is 6 feet longer than the width. find the length and width of the wall of the barn.

Sagot :

Area = length x width
 A= l x w      
  length is 6 ft longer than width, length = width + 6ft
Area = (w+6) x w
        40 sq ft=w^2+ 6w
w^2 + 6w - 40 = 0
(w + 10) (w - 4) = 0
w = -10ft and/or 4ft

distance can't be negative, so 4ft is width, length is 10ft
ProjectTermina
40 = l * w
l = w + 6

substitute (w + 6) in for l

40 = (w+6)*w
40 = w^2 + 6w
0 = w^2 + 6w - 40
0 = (w + 10) * (w - 4)

w + 10 = 0
w = -10

w - 4 = 0
w = 4

it does not make sense for the width to be negative, so 4 is the correct answer
now go back to one of the original equations, l = w + 6

l = w + 6
l = 4 + 6
l = 10



Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.