Answered

Westonci.ca is the best place to get answers to your questions, provided by a community of experienced and knowledgeable experts. Discover solutions to your questions from experienced professionals across multiple fields on our comprehensive Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

the area of a rectangular wall of a barn is 40 square feet. its length is 6 feet longer than the width. find the length and width of the wall of the barn.

Sagot :

Area = length x width
 A= l x w      
  length is 6 ft longer than width, length = width + 6ft
Area = (w+6) x w
        40 sq ft=w^2+ 6w
w^2 + 6w - 40 = 0
(w + 10) (w - 4) = 0
w = -10ft and/or 4ft

distance can't be negative, so 4ft is width, length is 10ft
ProjectTermina
40 = l * w
l = w + 6

substitute (w + 6) in for l

40 = (w+6)*w
40 = w^2 + 6w
0 = w^2 + 6w - 40
0 = (w + 10) * (w - 4)

w + 10 = 0
w = -10

w - 4 = 0
w = 4

it does not make sense for the width to be negative, so 4 is the correct answer
now go back to one of the original equations, l = w + 6

l = w + 6
l = 4 + 6
l = 10



Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.