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Sagot :
[tex]8^{3x - 1} = 2^8 ; 8 = 2^3 \\
(2^3)^{3x-1} = 2^8 \\
2^{9x-3} = 2^8 \\
9x-3=8 \\
9x=11 \\
x= \frac{11}{9} [/tex]
[tex]8^{(3x-1)}=2^8 \\\\ 2^{3(3x-1)}=2^8 \\\\ 3(3x-1)=8 \\\\ 9x-3=8 \\\\ 9x=8+3 \\\\ 9x=11 \\\\ \boxed{x=\frac{11}{9}}[/tex]
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